From the magnetic behaviour of (paramagnetic) and (diamagnetic), choose the correct geometry and oxidation state.
- (A), square planar
, square planar - (B), tetrahedral
, tetrahedral✓ Correct - (C), tetrahedral
, square planar - (D), tetrahedral
, square planar
Answer: (B)
Solution
In , nickel is , . is a weak-field ligand, so the complex adopts hybridisation and tetrahedral geometry, retaining two unpaired -electrons — consistent with its observed paramagnetism.
In , nickel is in the zero oxidation state, once the electrons redistribute into . With a full shell all electrons are paired, and the complex is again , tetrahedral — consistent with its diamagnetism.
is , tetrahedral, and is , tetrahedral.
In , nickel is in the zero oxidation state, once the electrons redistribute into . With a full shell all electrons are paired, and the complex is again , tetrahedral — consistent with its diamagnetism.
is , tetrahedral, and is , tetrahedral.
JEE Main · 2025 · 22 Jan 2025 · Shift 1 · Single correct option