Question

Match List-I with the List-II

**List-I (Reaction)**

(A) $\mathrm{N}_{2(\mathrm{~g})}+\mathrm{O}_{2(\mathrm{~g})} ightarrow 2 \mathrm{NO}_{(\mathrm{g})}$

(B) $2 \mathrm{~Pb}\left(\mathrm{NO}_{3}ight)_{2(\mathrm{~s})} ightarrow 2 \mathrm{PbO}_{(\mathrm{s})}+4 \mathrm{NO}_{2(\mathrm{~g})}+\mathrm{O}_{2(\mathrm{~g})}$

(C) $2 \mathrm{Na}_{(\mathrm{s})}+2 \mathrm{H}_{2} \mathrm{O}_{(\mathrm{l})} ightarrow 2 \mathrm{NaOH}_{(\mathrm{aq} .)}+\mathrm{H}_{2(\mathrm{~g})}$

(D) $2 \mathrm{NO}_{2(\mathrm{~g})}+2^{-} \mathrm{OH}_{(	ext {aq. })} ightarrow \mathrm{NO}_{2(	ext { aq. })}^{-}+\mathrm{NO}_{3(	ext { aq. })}^{-}+\mathrm{H}_{2} \mathrm{O}_{(1)}$

**List-II (Type of redox reaction)**

(I) Decomposition

(II) Displacement

(III) Disproportionation

(IV) Combination

Choose the correct answer from the options given below:

Accepted Answer

: two elements combine into one compound — combination. : one compound breaks into several — decomposition. : sodium displaces hydrogen from water — displacement. : nitrogen (+4 in ) is simultaneously reduced to +3 ( ) and oxidised to +5 ( ) — disproportionation. So (A)-Combination, (B)-Decompositi…

JEE Main · 2024 · 06 Apr 2024 · Shift 2 · Redox Reactions and Electrochemistry

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