Let the area of a △PQR with vertices P(5,4),Q(−2,4) and R(a,b) be 35 square units. If its orthocenter and centroid are O(2,514) and C(c,d) respectively, then c+2d is equal to
(A)37
(B)3✓ Correct
(C)2
(D)38
Answer: (B)
Solution
Since P(5,4) and Q(−2,4) share the same y-coordinate, PQ is horizontal with length 7, and the altitude from R to PQ is vertical. So the orthocenter's x-coordinate equals R's x-coordinate: a=2.
Area=21(7)∣b−4∣=35⟹∣b−4∣=10
To fix the sign, use that PO must be perpendicular to QR (the altitude from P):
PO=(2−5,514−4)=(−3,−56),QR=(a+2,b−4)=(4,b−4)
−12−56(b−4)=0⟹b−4=−10⟹b=−6
So R=(2,−6). The centroid is
C=(35−2+2,34+4−6)=(35,32)
c+2d=35+34=3
JEE Main · 2025 · 23 Jan 2025 · Shift 1 · Single correct option