The conditions and consequence that favours the configuration in a metal complex are :
- (A)weak field ligand, high spin complex✓ Correct
- (B)strong field ligand, high spin complex
- (C)strong field ligand, low spin complex
- (D)weak field ligand, low spin complex
Answer: (A)
Solution
In an octahedral complex, crystal field splitting determines whether electrons pair up before occupying the higher set. A strong field ligand produces a large splitting that exceeds the pairing energy, so all four electrons crowd into before any occupies , giving the low-spin configuration .
A weak field ligand produces a small , smaller than the pairing energy, so the electrons follow Hund's rule and singly occupy all five d-orbitals before any pairing occurs, giving the high-spin configuration .
The condition that favours is a weak field ligand producing a high-spin complex.
A weak field ligand produces a small , smaller than the pairing energy, so the electrons follow Hund's rule and singly occupy all five d-orbitals before any pairing occurs, giving the high-spin configuration .
The condition that favours is a weak field ligand producing a high-spin complex.
JEE Main · 2025 · 24 Jan 2025 · Shift 2 · Single correct option