JEE Main · 2024 · 01 Feb 2024 · Shift 2 · Capacitance

In an electrical circuit drawn below the amount of charge stored in the capacitor is ______

μ C

Answer: 60

Solution

In steady state no current flows through the capacitor branch, so there is no potential drop across

R_{2}

and the full 10 V drives current only through

R_{1}

and

R_{3}

in series:

I = \frac{10}{4 + 6} = 1

A. With

R_{2}

carrying no current, the capacitor's voltage equals the drop across

R_{3}

V_{C} = I R_{3} = 1 \times 6 = 6

V. The charge stored is

q = C V_{C} = 10 \times 6 = 60 μ C

JEE Main · 2024 · 01 Feb 2024 · Shift 2 · Integer answer

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