In the given circuit, the voltage across load resistance $(\mathrm{R}_{\mathrm{L}})$ is:

JEE Main · 2024 · 30 Jan 2024 · Shift 2 · Current Electricity

In the given circuit, the voltage across load resistance

(R_{L})

is:

Answer: (A)

The circuit has a 15 V source feeding a germanium diode

D_{1}

(forward drop

0.3 V

) in series with a silicon diode

D_{2}

(forward drop

0.7 V

), a series resistance of

1.5 k Ω

, and a load resistance

R_{L} = 2.5 k Ω

. Both diodes are forward biased and conduct.

The net EMF driving the circuit after subtracting both diode drops is

15 - 0.3 - 0.7 = 14 V

The total series resistance is

1.5 k Ω + 2.5 k Ω = 4 k Ω

The circuit current is

i = \frac{14 V}{4 k Ω} = 3.5 mA

The voltage across the load resistance is

V_{L} = i R_{L} = 3.5 mA \times 2.5 k Ω = 8.75 V

JEE Main · 2024 · 30 Jan 2024 · Shift 2 · Single correct option