Two cells are connected in opposition as shown. Cell $\mathrm{E}_{1}$ is of 8 V emf and $2 \Omega$ internal resistance; the cell $\mathrm{E}_{2}$ is of 2 V emf and $4 \Omega$ internal resistance. The terminal potential difference of cell $\mathrm{E}_{2}$ is:

JEE Main · 2024 · 30 Jan 2024 · Shift 1 · Current Electricity

Two cells are connected in opposition as shown. Cell

E_{1}

is of 8 V emf and

2Ω

internal resistance; the cell

E_{2}

is of 2 V emf and

4Ω

internal resistance. The terminal potential difference of cell

E_{2}

is:

Answer: 6

Net emf

= 8 - 2 = 6 V

; total resistance

= 2 + 4 = 6 Ω

, so

I = 1 A

.

Terminal p.d. of

E_{2}

: going from C to B,

V_{C} - 2 - 4 (1) = V_{B} \Rightarrow V_{C} - V_{B} = 6 V

JEE Main · 2024 · 30 Jan 2024 · Shift 1 · Integer answer