The type of hybridization and the magnetic property of $\left[\mathrm{MnCl}_{6}\right]^{3-}$ are :

(B) $s p^{3} d^{2}$, paramagnetic with four unpaired electrons

(A) $\mathrm{d}^{2} \mathrm{sp}^{3}$, paramagnetic with four unpaired electrons

(C) $d^{2} s p^{3}$, paramagnetic with two unpaired electrons

(D) $\mathrm{sp}^{3} \mathrm{~d}^{2}$, paramagnetic with two unpaired electrons

JEE Main · 2025 · 02 Apr 2025 · Shift 2 · Coordination Compounds

The type of hybridization and the magnetic property of

[MnCl_{6}]^{3 -}

are :

Answer: (B)

[MnCl X_{6}] X^{3 -}

the metal is

Mn X^{3 +}

[Ar] 3 d^{4}

. Chloride is a weak-field ligand, so the 3d electrons stay unpaired and the inner d orbitals are not used; bonding employs the outer orbitals in an

s p^{3} d^{2}

set, giving octahedral geometry. The four unpaired d electrons make the complex paramagnetic. The hybridisation is

s p^{3} d^{2}

and the complex is paramagnetic with four unpaired electrons.

JEE Main · 2025 · 02 Apr 2025 · Shift 2 · Single correct option