Given below are two statements Statements-I : The number of paramagnetic species among \(\left[\mathrm{CoF}_{6}\right]^{3-}, \quad\left[\mathrm{TiF}_{6}\right]^{3-}, \quad \mathrm{V}_{2} \mathrm{O}_{5}\) and \(\left[\mathrm{Fe}(\mathrm{CN})_{6}\right]^{3-}\) is 3 . Statement-II : \(\mathrm{K}_{4}\left[\mathrm{Fe}(\mathrm{CN})_{6}\right]<\mathrm{K}_{3}\left[\mathrm{Fe}(\mathrm{CN})_{6}\right]< \left[\mathrm{Fe}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right] \mathrm{SO}_{4} \cdot \mathrm{H}_{2} \mathrm{O}<\left[\mathrm{Fe}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right] \mathrm{Cl}_{3}\) is the correct order in terms of number of unpaired electron(s) in the complexes. In the light of the above statements, choose the correct answer from the options given below.

(A) Both statement-I and statement-II are true

(B) Both statement-I and statement-II are false

(C) Statement-I is true but statement-II is false

(D) Statement-I is false but statement-II is true

JEE Main · 2026 · 24 Jan 2026 · Shift 1 · Coordination Compounds

Given below are two statements

Statements-I : The number of paramagnetic species among

[CoF_{6}]^{3 -}, [TiF_{6}]^{3 -}, V_{2} O_{5}

and

[Fe (CN)_{6}]^{3 -}

is 3 .
Statement-II :

K_{4} [Fe (CN)_{6}] < K_{3} [Fe (CN)_{6}] < [Fe (H_{2} O)_{6}] SO_{4} \cdot H_{2} O < [Fe (H_{2} O)_{6}] Cl_{3}

is the correct order in terms of number of unpaired electron(s) in the complexes.
In the light of the above statements, choose the correct answer from the options given below.

(A)Both statement-I and statement-II are true✓ Correct
(B)Both statement-I and statement-II are false
(C)Statement-I is true but statement-II is false
(D)Statement-I is false but statement-II is true

Answer: (A)

Solution

In Statement I,

[Co F_{6}]^{3 -}

(

C o^{3 +}

d^{6}

, weak field) has four unpaired electrons,

[Ti F_{6}]^{3 -}

(

T i^{3 +}

d^{1}

) has one,

V_{2} O_{5}

(

V^{5 +}

d^{0}

) has none, and

[Fe (CN)_{6}]^{3 -}

(

F e^{3 +}

d^{5}

, strong field) has one, so three of the four species are paramagnetic and Statement I is correct. In Statement II,

K_{4} [Fe (CN)_{6}]

has

0

K_{3} [Fe (CN)_{6}]

has

1

[Fe (H_{2} O)_{6}] S O_{4} \cdot H_{2} O

has

4

and

[Fe (H_{2} O)_{6}] C l_{3}

has

5

unpaired electrons, so the order

0 < 1 < 4 < 5

holds. Both statements are true.

JEE Main · 2026 · 24 Jan 2026 · Shift 1 · Single correct option

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JEE Main · 2026 · 24 Jan 2026 · Shift 1 · Coordination Compounds

Solution

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