JEE Main · 2023 · 10 Apr 2023 · Shift 2 · Kinematics

Two projectiles are projected at

3 0^{\circ}

and

6 0^{\circ}

with the horizontal with the same speed. The ratio of the maximum height attained by the two projectiles respectively is:

(A) $2 : 3$
(B) $3 : 1$
(C) $1 : 3$ ✓ Correct
(D) $1 : 3$

Answer: (C)

Solution

The maximum height in projectile motion is

H_{m a x} = \frac{u ^{2} s i n ^{2} θ}{2 g}

. For the same initial speed

u

\frac{H _{1}}{H _{2}} = \frac{s i n ^{2} 3 0 ^{\circ}}{s i n ^{2} 6 0 ^{\circ}} = \frac{( 1/2 ) ^{2}}{( 3 /2 ) ^{2}} = \frac{1/4}{3/4} = \frac{1}{3}

JEE Main · 2023 · 10 Apr 2023 · Shift 2 · Single correct option

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