JEE Main · 2023 · 11 Apr 2023 · Shift 1 · Coordination Compounds

The set which does not have ambidentate ligand(s) is

(A) $C_{2} O_{4}^{2 -}$ , ethylene diammine, $H_{2} O$ ✓ Correct
(B) $EDTA^{4 -}, NCS^{-}, C_{2} O_{4}^{2 -}$
(C) $NO_{2}^{-}, C_{2} O_{4}^{2 -}$ , EDTA $^{4 -}$
(D) $C_{2} O_{4}^{2 -}, NO_{2}^{-}, NCS^{-}$

Answer: (A)

Solution

An ambidentate ligand can bind the metal through either of two different donor atoms. Of the species listed, only

NO X_{2} X^{-}

(N-bound nitro or O-bound nitrito) and

NCS X^{-}

(N-bound isothiocyanato or S-bound thiocyanato) are ambidentate. Oxalate

C X_{2} O X_{4} X^{2 -}

and

EDTA X^{4 -}

are chelating polydentate ligands, ethylenediamine is a bidentate nitrogen donor, and

H X_{2} O

is monodentate; none of these can switch donor atoms. The set made up of oxalate, ethylenediamine and water is therefore the one with no ambidentate ligand.

JEE Main · 2023 · 11 Apr 2023 · Shift 1 · Single correct option

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JEE Main · 2023 · 11 Apr 2023 · Shift 1 · Coordination Compounds

Solution

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