Given below are two statements :
Statements I : Ethene at 333 to 343 K and 6-7 atm pressure in the presence of and undergoes addition polymerization to give LDP.
Statement II : Caprolactam at 533-543 K in through step growth polymerizes to give Nylon 6.
In the light of the above Statements, chose the correct answer from the options given below :
Statements I : Ethene at 333 to 343 K and 6-7 atm pressure in the presence of and undergoes addition polymerization to give LDP.
Statement II : Caprolactam at 533-543 K in through step growth polymerizes to give Nylon 6.
In the light of the above Statements, chose the correct answer from the options given below :
- (A)Both Statement I and Statement II are true.
- (B)Statement I is false but Statement II is true.✓ Correct
- (C)Statement I is true but Statement II is false.
- (D)Both Statement I and Statement II are false.
Answer: (B)
Solution
Statement I is false. Ethene polymerization using Ziegler-Natta catalyst ( and ) at the given conditions produces HDPE (high-density polyethylene), not LDP (low-density polyethylene). LDP is produced by free radical polymerization at high pressure.
Statement II is true. Caprolactam undergoes ring-opening polymerization in the presence of water at 533-543 K to form Nylon-6 through step-growth polymerization.
Statement II is true. Caprolactam undergoes ring-opening polymerization in the presence of water at 533-543 K to form Nylon-6 through step-growth polymerization.
JEE Main · 2023 · 11 Apr 2023 · Shift 2 · Single correct option