Evaluate ∫13∣2x−1∣dx.Answer: 6SolutionOn [1,3] we have 2x−1>0, so ∣2x−1∣=2x−1:∫13(2x−1)dx=[x2−x]13=(9−3)−(1−1)=6CBSE Class 12 Board · 2020 · Subjective