Evaluate: ∫0πecosx+e−cosxecosxdxAnswer: 2πSolutionLet I=∫0πecosx+e−cosxecosxdx. Apply ∫0af(x)dx=∫0af(a−x)dx with a=π; since cos(π−x)=−cosx:I=∫0πe−cosx+ecosxe−cosxdxAdding the two forms:2I=∫0πecosx+e−cosxecosx+e−cosxdx=∫0πdx=πHence I=2π.CBSE Class 12 Board · 2024 · Subjective