The value of ∫π/4π/2cotθcosec2θdθ is(A)21✓ Correct(B)−21(C)0(D)−8πAnswer: (A)SolutionPut t=cotθ⇒dt=−cosec2θdθ. When θ=4π,t=1; when θ=2π,t=0.∫π/4π/2cotθcosec2θdθ=∫10t(−dt)=∫01tdt=[2t2]01=21Correct option: (A) 21.CBSE Class 12 Board · 2024 · Single correct option