Evaluate: ∫0πsecxcosecxxtanxdxAnswer: 4π2SolutionSimplify the integrand: secxcosecxtanx=sin2x, so I=∫0πxsin2xdx.Apply x→π−x (with sin2(π−x)=sin2x): I=∫0π(π−x)sin2xdx.2I=π∫0πsin2xdx=π∫0π21−cos2xdx=π⋅2πHence I=4π2.CBSE Class 12 Board · 2008 · Subjective