Evaluate the following as limit of sums: ∫02(x2+x)dxAnswer: 314SolutionHere f(x)=x2+x, a=0, b=2, h=n2, nh=2.∫02f(x)dx=h→0limhr=0∑n−1f(rh)=h→0limhr=0∑n−1(r2h2+rh)=h→0lim[h36(n−1)n(2n−1)+h22(n−1)n]Writing in terms of nh=2 and letting n→∞:=3(nh)3+2(nh)2=38+24=38+2=314CBSE Class 12 Board · 2005 · Subjective