JEE Main · 2023 · 13 Apr 2023 · Shift 1 · Solutions

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Solution of 12 g of non - electrolyte (A) prepared by dissolving it in 1000 mL of water exerts the same osmotic pressure as that of 0.05 M glucose solution at the same temperature. The empirical formula of A is

CH_{2} O

. The molecular mass of A is ______ g. (Nearest integer)

Answer: 240

Solution

Isotonic solutions exert the same osmotic pressure and so have equal molar concentrations; the concentration of A therefore equals that of the glucose solution,

0.05 M

. With

12 g

dissolved to make one litre of solution, the molar mass is the mass divided by the number of moles,

M = \frac{12}{0.05 \times 1}

. Evaluating this gives the molecular mass of A as

240 g

JEE Main · 2023 · 13 Apr 2023 · Shift 1 · Integer answer

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