JEE Main · 2022 · 28 Jul 2022 · Shift 2 · Semiconductors

An n.p.n transistor with current gain

β = 100

in common emitter configuration is shown in figure. The output voltage of the amplifier will be

Answer: (B)

Solution

For a common-emitter amplifier, the voltage gain is

\frac{v _{out}}{v _{in}} = β \frac{R _{out}}{R _{in}}

.

Given

β = 100

R_{out} = 10

kΩ,

R_{in} = 1

kΩ, and

v_{in} = 1 0^{- 3}

v_{out} = \frac{100 \times 10 \times 1 0 ^{3}}{1 0 ^{3}} \times 1 0^{- 3} = 1

JEE Main · 2022 · 28 Jul 2022 · Shift 2 · Single correct option