JEE Main · 2022 · 26 Jul 2022 · Shift 2 · Semiconductors

The maximum and minimum voltage of an amplitude modulated signal are 60 V and 20 V respectively. The percentage modulation index will be:

Answer: (B)

Solution

The modulation index is given by

μ = \frac{V _{max} - V _{min}}{V _{max} + V _{min}}

. Substituting the values:

μ = \frac{60 - 20}{60 + 20} = \frac{40}{80} = 0.5

. Therefore, percentage modulation =

0.5 \times 100 = 50%

JEE Main · 2022 · 26 Jul 2022 · Shift 2 · Single correct option