If $\mathrm{O}_{2}$ gas is bubbled through water at 303 K, the number of millimoles of $\mathrm{O}_{2}$ gas that dissolve in 1 litre of water is ______. (Nearest Integer) (Given: Henry's Law constant for $\mathrm{O}_{2}$ at 303 K is 46.82 k bar and partial pressure of $\mathrm{O}_{2}=0.920$ bar) (Assume solubility of $\mathrm{O}_{2}$ in water is too small, nearly negligible)

JEE Main · 2022 · 29 Jul 2022 · Shift 1 · Solutions

O_{2}

gas is bubbled through water at 303 K, the number of millimoles of

O_{2}

gas that dissolve in 1 litre of water is ______. (Nearest Integer)
(Given: Henry's Law constant for

O_{2}

at 303 K is 46.82 k bar and partial pressure of

O_{2} = 0.920

bar)
(Assume solubility of

O_{2}

in water is too small, nearly negligible)

Answer: 1

Solution

Using Henry's Law:

p = K_{H} \times x

Where

x

is the mole fraction of

O X_{2}

in solution:

0.920 = 46.82 \times 1 0^{3} \times \frac{n _{O_{2}}}{n _{H_{2} O}}

For 1 L water:

n_{H_{2} O} = \frac{1000}{18} = 55.56

mol

n_{O_{2}} = \frac{0.920 \times 55.56}{46.82 \times 1 0 ^{3}} = 1.09 \times 1 0^{- 3} mol

In millimoles:

1.09 \times 1 0^{- 3} \times 1000 = 1.09

mmol

\approx 1

mmol

JEE Main · 2022 · 29 Jul 2022 · Shift 1 · Integer answer

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