Find the truth table for the function $Y$ of $A$ and $B$ represented in the following figure.

(A) | A | B | Y | | 0 | 0 | 1 | | 0 | 1 | 0 | | 1 | 0 | 1 | | 1 | 1 | 1 |

(B) | A | B | Y | | 0 | 0 | 0 | | 0 | 1 | 0 | | 1 | 0 | 0 | | 1 | 1 | 1 |

(C) | A | B | Y | | 0 | 0 | 0 | | 0 | 1 | 1 | | 1 | 0 | 0 | | 1 | 1 | 0 |

(D) | A | B | Y | | 0 | 0 | 0 | | 0 | 1 | 1 | | 1 | 0 | 1 | | 1 | 1 | 1 |

JEE Main · 2021 · 27 Jul 2021 · Shift 2 · Semiconductors

Find the truth table for the function

Y

A

and

B

represented in the following figure.

Answer: (A)

The upper gate forms

A \cdot B

and the inverter forms

\overset{ˉ}{B}

, and these two feed the OR gate, so

Y = A \cdot B + \overset{ˉ}{B} = A + \overset{ˉ}{B}

The output is therefore low only when

A = 0

and

B = 1

. For

A = 0, B = 0

the output is

1

; for

A = 0, B = 1

it is

0

; for

A = 1, B = 0

it is

1

; and for

A = 1, B = 1

it is

1

JEE Main · 2021 · 27 Jul 2021 · Shift 2 · Single correct option