JEE Main · 2021 · 01 Sep 2021 · Shift 2 · Semiconductors

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A carrier wave with amplitude of 250 V is amplitude modulated by a sinusoidal base band signal of amplitude 150 V. The ratio of minimum amplitude to maximum amplitude for the amplitude modulated wave is 50 :

x

, then value of

x

is ______.

Answer: 200

Solution

In amplitude modulation the envelope swings between

A_{c} + A_{m}

and

A_{c} - A_{m}

. The maximum is

250 + 150 = 400 V

and the minimum is

250 - 150 = 100 V

, so

A_{m i n} : A_{m a x} = 100 : 400 = 1 : 4

. Scaling the minimum to

50

makes this

50 : 200

, so

x = 200

JEE Main · 2021 · 01 Sep 2021 · Shift 2 · Integer answer

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