In the following sequence of reactions, (see reaction scheme) The compounds $\mathbf{B}$ and $\mathbf{C}$ respectively are:

(D) $\mathrm{CHI}_{3}, \mathrm{CH}_{3} \mathrm{COOK}$

(A) $\mathrm{Cl}_{3} \mathrm{COOK}, \mathrm{HCOOH}$

(B) $\mathrm{Cl}_{3} \mathrm{COOK}, \mathrm{CH}_{3} \mathrm{I}$

(C) $\mathrm{CH}_{3} \mathrm{I}, \mathrm{HCOOK}$

JEE Main · 2021 · 01 Sep 2021 · Shift 2 · Aldehydes Ketones and Carboxylic Acids

In the following sequence of reactions,
(see reaction scheme)
The compounds

B

and

C

respectively are:

(A) $Cl_{3} COOK, HCOOH$
(B) $Cl_{3} COOK, CH_{3} I$
(C) $CH_{3} I, HCOOK$
(D) $CHI_{3}, CH_{3} COOK$ ✓ Correct

Answer: (D)

Solution

Propene adds water by acid-catalysed Markovnikov addition to give propan-2-ol,

A

. Propan-2-ol contains the

C H_{3} CH (OH) -

grouping, so with alkaline hypoiodite it undergoes the iodoform reaction: the methyl carbinol is cleaved to iodoform and the potassium salt of the two-carbon acid. The products are

CH I_{3}

and

C H_{3} COOK

JEE Main · 2021 · 01 Sep 2021 · Shift 2 · Single correct option

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