Iodoform test can differentiate between A. Methanol and Ethanol B. \(\mathrm{CH}_{3} \mathrm{COOH}\) and \(\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{COOH}\) C. Cyclohexene and cyclohexanone D. Diethyl ether and Pentan-3-one E. Anisole and acetone Choose the correct answer from the options given below:

JEE Main · 2026 · 23 Jan 2026 · Shift 2 · Aldehydes Ketones and Carboxylic Acids

Iodoform test can differentiate between
A. Methanol and Ethanol
B.

CH_{3} COOH

and

CH_{3} CH_{2} COOH

C. Cyclohexene and cyclohexanone
D. Diethyl ether and Pentan-3-one
E. Anisole and acetone

Choose the correct answer from the options given below:

(A)A & E only✓ Correct
(B)A & D only
(C)A, B & E only
(D)B, C & E only

Answer: (A)

Solution

The iodoform test is given only by ethanol, by methyl carbinols

C H_{3} CH (OH) -

and by methyl ketones

C H_{3} CO -

. Methanol gives no precipitate while ethanol does, so that pair is distinguished, and anisole gives none while acetone does, so that pair is distinguished too. In contrast

C H_{3} COOH

and

C H_{3} C H_{2} COOH

both fail, cyclohexene and cyclohexanone both fail (cyclohexanone has no

C H_{3} CO -

group), and diethyl ether and pentan-3-one both fail, so none of those pairs can be told apart. The test separates only the methanol/ethanol and anisole/acetone pairs.

JEE Main · 2026 · 23 Jan 2026 · Shift 2 · Single correct option

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JEE Main · 2026 · 23 Jan 2026 · Shift 2 · Aldehydes Ketones and Carboxylic Acids

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