The mole fraction of glucose $\left(\mathrm{C}_{6} \mathrm{H}_{12} \mathrm{O}_{6}\right)$ in an aqueous binary solution is 0.1. The mass percentage of water in it, to the nearest integer, is ______.

JEE Main · 2020 · 03 Sep 2020 · Shift 1 · Solutions

The mole fraction of glucose

(C_{6} H_{12} O_{6})

in an aqueous binary solution is 0.1. The mass percentage of water in it, to the nearest integer, is ______.

Answer: 47

Solution

Take one mole of solution, in which the glucose mole fraction of

0.1

means

0.1

mol glucose and

0.9

mol water. Their masses are

0.1 \times 180 = 18

g of glucose and

0.9 \times 18 = 16.2

g of water, a total of

34.2

g. The mass percentage of water is

\frac{16.2}{34.2} \times 100 = 47.4%

, which rounds to

47

JEE Main · 2020 · 03 Sep 2020 · Shift 1 · Integer answer

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