JEE Main · 2019 · 11 Jan 2019 · Shift 2 · Polymers

The homopolymer formed from 4 - hydroxybutanoic acid is:

(A)(see structure)
✓ Correct
(B)(see structure)
(C)(see structure)
(D)(see structure)

Answer: (A)

Solution

4-hydroxybutanoic acid,

HO - CH X_{2} - CH X_{2} - CH X_{2} - COOH

, carries both an

-

OH and a

-

COOH group, so its molecules join head-to-tail by esterification, each linkage expelling a molecule of water. This condensation builds a polyester with the repeating unit

- O - CH X_{2} - CH X_{2} - CH X_{2} - CO X^{-}

JEE Main · 2019 · 11 Jan 2019 · Shift 2 · Single correct option

Practise more: all JEE Main PYQs on Polymers →

More JEE Main questions on Polymers

Polymer used in orlon is:
JEE Main 2023View solution →
Buna-S can be represented as:
JEE Main 2023View solution →
The polymer X - consists of linear molecules and is closely packed. It is prepared in the presence of triethylaluminium and titanium tetrachloride under low pressure. The polymer X is -
JEE Main 2023View solution →
Given below are two statements :

Statements I : Ethene at 333 to 343 K and 6-7 atm pressure in the presence of $AlEt_{3}$ and $TiCl_{4}$ undergoes addition polymerization to give LDP.

Statement II : Caprolactam at 533-543 K in $H_{2} O$ throu …
JEE Main 2023View solution →
Match List I with List II

LIST I (Examples) | LIST II (Type)
A. 2-Chloro-1,3-butadiene | I. Biodegradable polymer
B. Nylon 2-nylon 6 | II. Synthetic Rubber
C. Polyacrylonitrile | III. Polyester
D. Dacron | IV. Addition Polymer

Choose the correct answer from the options given be …
JEE Main 2023View solution →
Match List I with List II:

List I-(Monomer)
(A) Tetrafluoroethylene
(B) Acrylonitrile
(C) Caprolactam
(D) Isoprene

List II-(Polymer)
(i) Orlon
(ii) Natural rubber
(iii) Teflon
(IV) Nylon-6

Choose the correct answer from the options given below:
JEE Main 2023View solution →