In a common emitter amplifier circuit using an $\mathrm{n}-\mathrm{p}-\mathrm{n}$ transistor, the phase difference between the input and the output voltages will be :

JEE Main · 2017 · 02 Apr 2017 · Offline · Semiconductors

In a common emitter amplifier circuit using an

n - p - n

transistor, the phase difference between the input and the output voltages will be :

(A) $13 5^{\circ}$
(B) $18 0^{\circ}$ ✓ Correct
(C) $4 5^{\circ}$
(D) $9 0^{\circ}$

Answer: (B)

Solution

In a common-emitter amplifier the output is read at the collector. Push the base more positive and the collector current rises, the drop across the collector resistor grows, and the collector voltage falls; pull the input down and the output climbs. Input and output therefore move in exact opposition, a phase difference of

18 0^{\circ}

JEE Main · 2017 · 02 Apr 2017 · Offline · Single correct option

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JEE Main · 2017 · 02 Apr 2017 · Offline · Semiconductors

Solution

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