JEE Main · 2006 · 30 Apr 2006 · Offline · Conservation of Momentum

A bomb of mass 16 kg at rest explodes into two pieces of masses of 4 kg and 12 kg. The velocity of the 12 kg mass is

4 ms^{- 1}

. The kinetic energy of the other mass is

(A)96 J
(B)144 J
(C)288 J✓ Correct
(D)192 J

Answer: (C)

Solution

The bomb is initially at rest, so by conservation of momentum the two fragments carry equal and opposite momenta. The

12 kg

piece moves at

4 m/s

, giving it a momentum of

48 kg m/s

; the

4 kg

piece must therefore move at

\frac{48}{4} = 12 m/s

. Its kinetic energy is

\frac{1}{2} (4) (12)^{2} = 288 J

JEE Main · 2006 · 30 Apr 2006 · Offline · Single correct option

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