Match List I with List II:
List-I (Name of reaction): A. Hell-Volhard-Zelinsky reaction B. Iodoform reaction C. Etard reaction D. Gatterman-Koch reaction
List-II (Reagent used): I. NaOH + I₂ II. (i) CrO₂Cl₂, CS₂ (ii) H₂O III. (i) Br₂/red phosphorus (ii) H₂O IV. CO, HCl, anhyd. AlCl₃
Choose the correct answer from the options given below:
List-I (Name of reaction): A. Hell-Volhard-Zelinsky reaction B. Iodoform reaction C. Etard reaction D. Gatterman-Koch reaction
List-II (Reagent used): I. NaOH + I₂ II. (i) CrO₂Cl₂, CS₂ (ii) H₂O III. (i) Br₂/red phosphorus (ii) H₂O IV. CO, HCl, anhyd. AlCl₃
Choose the correct answer from the options given below:
- (A)A-III, B-II, C-I, D-IV
- (B)A-III, B-I, C-IV, D-II
- (C)A-I, B-II, C-III, D-IV
- (D)A-III, B-I, C-II, D-IV✓ Correct
Answer: (D)
Solution
Each named reaction is linked to its reagents. The Hell-Volhard-Zelinsky reaction uses bromine with red phosphorus followed by water to alpha-halogenate a carboxylic acid. The iodoform reaction uses sodium hydroxide with iodine. The Etard reaction uses chromyl chloride in carbon disulphide followed by hydrolysis to give an aldehyde from a methylbenzene. The Gattermann-Koch reaction uses carbon monoxide and hydrogen chloride with anhydrous aluminium chloride to formylate an arene. The correct pairing is Hell-Volhard-Zelinsky with bromine and red phosphorus, iodoform with sodium hydroxide and iodine, Etard with chromyl chloride, and Gattermann-Koch with carbon monoxide and hydrogen chloride.
JEE Main · 2023 · 06 Apr 2023 · Shift 1 · Single correct option