JEE Main · 2026 · 04 Apr 2026 · Shift 2 · Semiconductors

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A diode has Zener voltage of 10 V and maximum power dissipation of 0.5 W , then the minimum resistance to be used in series with this diode for safety when it is connected to a 25 V power supply is ______

Ω

Answer: 300

Solution

The largest current the diode can carry without exceeding its rated dissipation is

I = \frac{P}{V _{Z}} = \frac{0.5}{10} = 0.05 A

. Since the diode holds

10 V

, the series resistor carries

25 - 10 = 15 V

. Hence

R = \frac{15}{0.05} = 300 Ω

. The minimum series resistance for safe operation is

300 Ω

JEE Main · 2026 · 04 Apr 2026 · Shift 2 · Integer answer

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