JEE Main · 2026 · 05 Apr 2026 · Shift 1 · Semiconductors

The first gate is an OR gate, so its output is $A+B$; this node drives LED-1, which glows when $A+B=1$. The same node, together with input $C$, feeds the middle AND gate, giving $(A+B)\cdot C$. The final AND gate combines this with input $A$ carried along the top line, so the signal driving LED-2 is $A\cdot (A+B)\cdot C=A\cdot C$, and LED-2 glows when $A=1$ and $C=1$. Both LEDs glow only when $A+B=1$ along with $A=1$ and $C=1$, which is met by $A=1,B=0,C=1$.