JEE Advanced · 2013 · 02 Jun 2013 · Paper 1 · Application of Derivatives

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Let (the set of all real numbers) be a positive, non-constant and differentiable function such that and . Then the value of lies in the interval
  1. (A)
  2. (B)
  3. (C)
  4. (D)✓ Correct

Answer: (D)

Solution

From , we have . Multiplying by : , so is decreasing. For , , thus . Since , we have . Therefore, the integral lies in .

JEE Advanced · 2013 · 02 Jun 2013 · Paper 1 · Single correct option

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