Let (the set of all real numbers) be a positive, non-constant and differentiable function such that and . Then the value of lies in the interval
- (A)
- (B)
- (C)
- (D)✓ Correct
Answer: (D)
Solution
From , we have . Multiplying by : , so is decreasing. For , , thus . Since , we have . Therefore, the integral lies in .
JEE Advanced · 2013 · 02 Jun 2013 · Paper 1 · Single correct option