JEE Main · 2021 · 24 Feb 2021 · Shift 1 · Polymers

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Match List I with List II.

List I (Monomer Unit):
(a) Caprolactum
(b) 2-Chloro-1,3-butadiene
(c) Isoprene
(d) Acrylonitrile

List II (Polymer):
(i) Natural rubber
(ii) Buna- N
(iii) Nylon 6
(iv) Neoprene

Choose the correct answer from the options given below :

Answer: A → III, B → IV, C → I, D → II

Solution

The correct matching of monomers to their polymers:

(a) Caprolactum → (iii) Nylon 6
  • Caprolactam (ε-caprolactam) undergoes ring-opening polymerization to form Nylon 6
  • Structure: cyclic amide with 6 carbons
  • Polymerization: (caprolactam) → [–NH–(CH₂)₅–CO–]ₙ

(b) 2-Chloro-1,3-butadiene → (iv) Neoprene
  • 2-Chloro-1,3-butadiene (chloroprene) polymerizes to form neoprene (polychloroprene)
  • Neoprene is a synthetic rubber with good chemical resistance

(c) Isoprene → (i) Natural rubber
  • Isoprene (2-methyl-1,3-butadiene) is the monomer of natural rubber
  • Natural rubber is cis-1,4-polyisoprene
  • Found in latex from rubber trees

(d) Acrylonitrile → (ii) Buna-N
  • Buna-N is a copolymer of 1,3-butadiene and acrylonitrile
  • Also called nitrile rubber (NBR)
  • Has good oil and fuel resistance

Therefore, the correct matching is: (a)→(iii), (b)→(iv), (c)→(i), (d)→(ii)

JEE Main · 2021 · 24 Feb 2021 · Shift 1 · Match the columns

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