A player caught a cricket ball of mass 150 g moving at a speed of $20 \mathrm{~m}/\mathrm{s}$. If the catching process is completed in 0.1 s, the magnitude of force exerted by the ball on the hand of the player is:

JEE Main · 2024 · 08 Apr 2024 · Shift 1 · Conservation of Momentum

A player caught a cricket ball of mass 150 g moving at a speed of

20 m / s

. If the catching process is completed in 0.1 s, the magnitude of force exerted by the ball on the hand of the player is:

(A)150 N
(B)3 N
(C)30 N✓ Correct
(D)300 N

Answer: (C)

Solution

By the impulse–momentum theorem

F = \frac{Δ p}{Δ t} = \frac{m v}{Δ t}

(ball brought to rest):

F = \frac{0.15 \times 20}{0.1} = 30 N

Option (C).

JEE Main · 2024 · 08 Apr 2024 · Shift 1 · Single correct option

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