JEE Main · 2024 · 01 Feb 2024 · Shift 1 · Solutions

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We have three aqueous solutions of NaCl labelled as 'A', 'B' and 'C' with concentration 0.1 M, 0.01 M & 0.001 M, respectively. The value of van t' Hoff factor (i) for these solutions will be in the order.

(A) $i_{A} < i_{B} < i_{C}$ ✓ Correct
(B) $i_{A} < i_{C} < i_{B}$
(C) $i_{A} = i_{B} = i_{C}$
(D) $i_{A} > i_{B} > i_{C}$

Answer: (A)

Solution

Van't Hoff factor

i

for a strong electrolyte like NaCl approaches its theoretical value (

i = 2

) as the solution becomes more dilute, because ionic dissociation is more complete and inter-ionic attraction (which suppresses effective dissociation) is weaker at lower concentration. Since A (0.1 M) is most concentrated, B (0.01 M) less so, and C (0.001 M) most dilute:

i_{A} < i_{B} < i_{C}

JEE Main · 2024 · 01 Feb 2024 · Shift 1 · Single correct option

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