JEE Main · 2025 · 07 Apr 2025 · Shift 2 · Solutions

Chloroform and acetone attract one another through hydrogen bonding between the unlike molecules, giving negative deviation from Raoult's law and a maximum boiling azeotrope. Ethanol and water, on mixing, break their own hydrogen bonds and show positive deviation, giving a minimum boiling azeotrope. Benzene and toluene are so alike that mixing changes neither the volume nor the enthalpy, so $\Delta V_{mix}=0$, the mark of an ideal solution. Acetic acid dissolved in benzene exists as hydrogen-bonded dimers. Hence chloroform with acetone goes with the maximum boiling azeotrope, ethanol with water with the minimum boiling azeotrope, benzene with toluene with $\Delta V_{mix}=0$, and acetic acid in benzene with dimerization.