JEE Main · 2023 · 10 Apr 2023 · Shift 1 · Semiconductors

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A zener diode of power rating 1.6 W is to be used as voltage regulator. If the zener diode has a breakdown of 8 V and it has to regulate voltage fluctuating between 3 V and 10 V. The value of resistance

R_{s}

for safe operation of diode will be:

(A) $13.3Ω$
(B) $12Ω$
(C) $10Ω$ ✓ Correct
(D) $13Ω$

Answer: (C)

Solution

The diode clamps its branch at the breakdown voltage

V_{z} = 8

V, and its rated power fixes the greatest current it may safely pass:

i_{m a x} = \frac{P}{V _{z}} = \frac{1.6}{8} = 0.2

A. The worst case is the highest input,

10

V, where the series resistor must drop the surplus

10 - 8 = 2

V. Therefore

R_{s} = \frac{V _{in,max} - V _{z}}{i _{m a x}} = \frac{2}{0.2} = 10 Ω

JEE Main · 2023 · 10 Apr 2023 · Shift 1 · Single correct option

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