JEE Main · 2023 · 10 Apr 2023 · Shift 1 · Conservation of Momentum

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A particle of mass m moving with velocity v collides with a stationary particle of mass 2m. After collision, they stick together and continue to move together with velocity

(A)v
(B) $\frac{v}{2}$
(C) $\frac{v}{3}$ ✓ Correct
(D) $\frac{v}{4}$

Answer: (C)

Solution

The collision is perfectly inelastic, so the bodies coalesce while linear momentum is conserved. Momentum before equals momentum after:

m v = (m + 2 m) v^{'}

. Hence

v^{'} = \frac{m v}{3 m} = \frac{v}{3}

JEE Main · 2023 · 10 Apr 2023 · Shift 1 · Single correct option

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