JEE Main · 2023 · 12 Apr 2023 · Shift 1 · Semiconductors

In an n-p-n common emitter (CE) transistor the collector current changes from 5 mA to 16 mA for the change in base current from

100 μ A

and

200 μ A

, respectively. The current gain of transistor is ______.

Answer: (A)

Solution

The current gain in a common emitter configuration is given by

β = \frac{Δ I _{C}}{Δ I _{B}}

. Here,

Δ I_{C} = 16 mA - 5 mA = 11 mA

and

Δ I_{B} = 200 μ A - 100 μ A = 100 μ A

. Therefore,

β = \frac{11 mA}{100 μ A} = \frac{11 \times 1 0 ^{- 3}}{100 \times 1 0 ^{- 6}} = 110

JEE Main · 2023 · 12 Apr 2023 · Shift 1 · Single correct option