JEE Advanced · 2018 · 20 May 2018 · Paper 2 · Compounds Containing Nitrogen

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Aniline reacts with mixed acid (conc. and conc. ) at 288 K to give P (51%), Q (47%) and R (2%). The major product(s) of the following reaction sequence is (are)



R S:
1) , pyridine
2) ,
3)
4) , HCl / 273-278 K
5) EtOH,

S major product(s):
1) Sn / HCl
2) (excess)
3) , HCl / 273-278 K
4)
  1. (A)(see structure)
  2. (B)(see structure)
  3. (C)(see structure)
  4. (D)(see structure)
    ✓ Correct

Answer: (D)

Solution

Aniline reacts with mixed acid to give m-nitroaniline (P, 51%), p-nitroaniline (Q, 47%), and o-nitroaniline (R, 2%). The reaction sequence involves: (1) acetylation to protect the amino group, (2) bromination at ortho positions, (3) deprotection, (4) diazotization, (5) reduction to remove the diazo group. The major product P (m-nitroaniline) undergoes this sequence. After Sn/HCl reduction of the nitro group to amino, bromination in excess gives tribromination at positions 2, 4, and 6. Diazotization followed by removes the amino group, giving 1,3,5-tribromobenzene (option D).

JEE Advanced · 2018 · 20 May 2018 · Paper 2 · One or more correct options

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