(C)(A): (see structure) (B): (see structure)AB✓ Correct
(D)(A): (see structure) (B): (see structure)AB
Answer: (C)
Solution
The reaction sequence involves:
Formation of A (benzonitrile): Aniline reacts with chloroform (CHCl₃) and alcoholic KOH in the carbylamine reaction (isocyanide test). However, under these conditions with proper workup, benzonitrile (C₆H₅CN) is formed as product A.
Formation of B (benzaldehyde): Benzonitrile undergoes partial reduction with SnCl₂/HCl (Stephen reduction) to form an imine intermediate, which upon hydrolysis gives benzaldehyde (C₆H₅CHO) as product B.