JEE Main · 2024 · 04 Apr 2024 · Shift 1 · Compounds Containing Nitrogen

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X g of ethylamine is subjected to reaction with NaNO₂/HCl followed by water; evolved dinitrogen gas which occupied 2.24 L volume at STP.

X is ____ × 10⁻¹ g.

Answer: 45

Solution

Ethylamine with

NaN O_{2} /HCl

(then water) gives ethanol and nitrogen gas:

C H_{3} C H_{2} N H_{2} NaN O_{2} /HCl, H_{2} O C H_{3} C H_{2} OH + N_{2} .

n_{N_{2}} = \frac{2.24}{22.4} = 0.1 mol \Rightarrow n_{amine} = 0.1 mol .

Mass

= 0.1 \times 45 = 4.5

= 45 \times 1 0^{- 1}

g. So

X =

45.

JEE Main · 2024 · 04 Apr 2024 · Shift 1 · Integer answer

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