From 6.55 g of aniline, the maximum amount of acetanilide that can be prepared will be _____ ×10−1 g.
Answer: 95
Solution
Aniline (M=93 g/mol) is acetylated 1:1 to acetanilide (M=135 g/mol). Moles of aniline =936.55=0.0704 mol. Mass of acetanilide =0.0704×135=9.5 g=95×10−1 g.Reaction scheme