X of enthanamine was subjected to reaction with \(\mathrm{NaNO}_{2} / \mathrm{HCl}\) followed by hydrolysis to liberate \(\mathrm{N}_{2}\) and HCl . The HCl generated was completely neutralised by 0.2 moles of NaOH . X is ____ g.

JEE Main · 2024 · 05 Apr 2024 · Shift 2 · Compounds Containing Nitrogen

X of enthanamine was subjected to reaction with

NaNO_{2} / HCl

followed by hydrolysis to liberate

N_{2}

and HCl . The HCl generated was completely neutralised by 0.2 moles of NaOH . X is ____ g.

Answer: 9

Solution

Ethylamine reacts with

N a N O_{2} / H C l

to give an aliphatic diazonium salt, which is unstable and hydrolyses immediately:

C_{2} H_{5} N H_{2} + H N O_{2} \to C_{2} H_{5} O H + N_{2} + H_{2} O

Overall, each mole of amine consumes one mole of HCl in forming the diazonium salt, and this same amount of HCl is regenerated on hydrolysis — so the HCl neutralised by NaOH corresponds mole-for-mole to the amine taken.
Moles of amine = moles of NaOH = 0.2. Molar mass of

C_{2} H_{5} N H_{2} = 45

g/mol, so

X = 0.2 \times 45 = 9 g

JEE Main · 2024 · 05 Apr 2024 · Shift 2 · Integer answer

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JEE Main · 2024 · 05 Apr 2024 · Shift 2 · Compounds Containing Nitrogen

Solution

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