C2H5Br with alcoholic KOH undergoes E2 dehydrohalogenation to give ethylene, A=CH2=CH2. Ethylene adds Br2 in CCl4 to give 1,2-dibromoethane, B=BrCH2CH2Br. Treating B with excess KCN displaces both bromides by SN2 substitution to give succinonitrile, C=NC−CH2CH2−CN. Hydrolysis of both nitrile groups with excess H3O+ converts them to carboxylic acids, giving D=HOOC−CH2CH2−COOH, succinic acid.Reaction scheme
JEE Main · 2024 · 01 Feb 2024 · Shift 2 · Single correct option