Identify [A], [B], and [C], respectively in the following reaction sequence :
(A)(see structures)ABC
(B)(see structures)ABC
(C)(see structures)ABC✓ Correct
(D)(see structures)ABC
Answer: (C)
Solution
Treating [A] with NaNO2 and HCl at 273--278 K forms the benzenediazonium ion, so [A] is aniline. Warming the diazonium salt with potassium iodide replaces the diazonium group by iodine, giving iodobenzene as [B]. Iodobenzene with sodium in dry ether couples two aryl halides through the Fittig reaction, joining the rings as biphenyl, which is [C]. Thus [A], [B] and [C] are aniline, iodobenzene and biphenyl.
JEE Main · 2025 · 03 Apr 2025 · Shift 1 · Single correct option